To take the next step — and we’re close to the finish line! — note that the proof doesn’t put any constraint on the upper value of K. If we choose some definite K1, the proof establishes the existence of a single 2-good pair, which we can label a1 and b1. If we choose K2, it proves the existence of a pair we’ll call a2 and b2; that pair may or may not produce a functionally different approximation of r. Maybe there’s just a single solution that repeats for every K?
https://www.sciencefocus.com/future-technology/does-a-usb-drive-get-heavier-as-you-store-more-files-on-it
。同城约会是该领域的重要参考
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